This is the given situation.
Where m is the mass of the block and g is the acceleration due to gravity. It is given in the question, mg=150 pound=68.04 kg.
There are two components of weight. One along with x-direction and the other with negative y-direction.
x-component is
[tex]mg\sin \theta[/tex]y-component is
[tex]mg\cos \theta[/tex]Tension on the string is equal to the x-component of the weight. and the normal force,i.e. perpendicular force is equal and opposite to the y component of the weight. But tension is in opposite direction to the x-component of weight and perpendicular force is opposite to the y-component.
Therefore the tension is,
[tex]T=-mg\sin \theta=-68.04\times\sin 35^o=-39.03\text{ N}[/tex]And the normal force is,
[tex]N=mg\cos \theta=60.04\times\cos 35^o=55.74\text{ N}[/tex]Therefore the magnitude of the tension on the string is 39.03 N
And the normal force is 55.74 N
