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Which equation can be used to find the solution of (1/4)y+1=64 ? −y−1=3y−1=3−y+1=3y + 1 = 3

Which Equation Can Be Used To Find The Solution Of 14y164 Y13y13y13y 1 3 class=

Sagot :

[tex](\frac{1}{4})^{y+1}=64[/tex]

1/4 and 64 can be expressed as follows:

[tex]\begin{gathered} \frac{1}{4}=4^{-1} \\ 64=4^3 \end{gathered}[/tex]

Substituting into the equation:

[tex]\begin{gathered} (4^{-1})^{y+1}=4^3 \\ 4^{(-1)(y+1)}=4^3 \\ 4^{-y-1}=4^3 \\ -y-1=3 \end{gathered}[/tex]