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For the following set of data, find the number of data within 1 population standarddeviation of the mean.68, 68, 70, 61, 67, 71, 63, 67

For The Following Set Of Data Find The Number Of Data Within 1 Population Standarddeviation Of The Mean68 68 70 61 67 71 63 67 class=

Sagot :

Given the following set of numbers,

[tex]68,\text{ 68, 70, 61, 67, 71, 63, 67}[/tex]

Where the (n) number of data is 8, the mean is,

[tex]\bar{x}=\frac{x_1+x_2+..._{}+x_n}{n}=\frac{68+68+70+61+67+71+63+67}{8}=66.875[/tex]

The standard deviation is 3.36

Hence, the interval that is 1 population within the mean is given by

[tex](66.88-3.36,66.88+3.36)=(63.52,70.24)[/tex]

Of all the data only 71, 61, and 63 are not an element of the interval (63.52,70.24)

The total number of data is 8.

Hence, the total number of data within 1 standard deviation of the mean is 5

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