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Sample proportions of size ten were taken from a group of students. Students were asked if they wore glasses while watching TV. The proportion that wore glasses while watching TV was recorded. The standard deviation of the data is 0.19 The margin of error can be given by the formula Margin ferror = 2 * s/(sqrt(n)) where s is the standard deviation and n is the sample size . What is the margin of error for the data collected ?

Sample Proportions Of Size Ten Were Taken From A Group Of Students Students Were Asked If They Wore Glasses While Watching TV The Proportion That Wore Glasses W class=

Sagot :

Margin of error:

[tex]ME=2\times\frac{s}{\sqrt{n}}[/tex]

For the given data collected

[tex]\begin{gathered} s=0.19 \\ n=10 \\ \\ ME=2\times\frac{0.19}{\sqrt{10}}=\frac{0.38}{\sqrt{10}}=0.12 \end{gathered}[/tex]

Then, the margin of error is 0.12

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