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Suppose that you want to buy 6 different books and the order that you buy them does not matter. Then thenumber of ways to choose 6 books from 44 available books is

Sagot :

We have that the order doesn't matter without repetition, so should use combinations that are represented by the next formula:

[tex]C=\frac{n!}{r!(n-r)!}[/tex]

Where n is the total of books and r the numbers of the group, in this case, 6 differents books.

Replace these values:

[tex]\frac{44!}{6!(44-6)!}[/tex][tex]C=\frac{44!}{6!(38)!}=7059052\text{ ways to choose 6 books from 44 available}[/tex]

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