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Sagot :
(a). From the given table,
R(0)=226.6
R(10)=205.6
The average rate of change for the temperature from 0 minutes to 10 minutes is
[tex]\begin{gathered} A=\frac{R(10)-R(0)}{10-0} \\ =\frac{205.6-226.6}{10} \\ =-2.1 \end{gathered}[/tex](a) The average rate of change for the temperature from 0 minutes to 10 minutes is -2.1 (in degree centrigrade)
Minus sign implies that the temperature is deacreasing with increasing time
(b). Again,
R(30)=157.6
R(50)=119.6
The average rate of change for the temperature from 30 minutes to 50 minutes is
[tex]\begin{gathered} A=\frac{R(50)-R(30)}{50-30} \\ =\frac{119.6-157.6}{20} \\ =-1.9 \end{gathered}[/tex](b) The average rate of change for the temperature from 30 minutes to 50 minutes is -1.9 (in degree centrigrade)
Minus sign implies that the temperature is deacreasing with increasing time
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