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Sagot :
The rule of the volume of the solid shaped a rectangular solid is
[tex]V=L\times W\times H[/tex]L is the length
W is the width
H is the height
Since the dimensions of the room are
10 m long
5.6 m wide
155 m high
Then
L = 10
W = 5.6
H = 155
Substitute them in the rule above
[tex]\begin{gathered} V=10\times5.6\times155 \\ V=8680m^3 \end{gathered}[/tex]The volume of the room is 8680 cubic meters
The rule of the mass is
[tex]m=d\times V[/tex]m is the mass
d is the density
V is the volume
Since the density is 1.506 kg/m^3
Then d = 1.506
Since the volume is 8680 m^3
Then
[tex]\begin{gathered} m=1.506\times8680 \\ m=13072.08\operatorname{kg} \end{gathered}[/tex]The mass of the smoke inside the room is 13072.08 kg
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