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Find an equation of the line that satisfies the conditionPasses through (-1,-3) and (4,2)

Find An Equation Of The Line That Satisfies The ConditionPasses Through 13 And 42 class=

Sagot :

The points given are:

(-1, -3) and (4, 2)

Coordinates are:

x₁ =-1 y₁=-3 x₂ = 4 y₂ = 2

First, let's find the slope(m) of the equation using the formula below:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex][tex]=\frac{2+3}{4+1}=\frac{5}{5}=1[/tex]

Next, find the inetercept of the equation by substituting x =-1 y=-3 m = 1 into y=mx+ b

-3 = 1(-1) + b

-4 = -1 + b

Add 1 to bothside

-4+1 = b

-3 = b

b = -3

We can now form the equation of the line by simply substituting the value of m and b into y=mx+ b

y = x - 3

Therefore, the equation of the line that satisfies the condition is y = x - 3

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