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Sagot :
You have to find the equation of the linear function h(x), given that you know two points of the said function.
h(3)=-2 → this notation indicates the ordered pair (3,-2)
h(-3)=16 → this notation indicates the ordered pair (-3,16)
The first step to determine the equation of any line or linear function is to calculate its slope. To do so you have to use the following formula:
[tex]m=\frac{y_1-y_2}{x_1-x_2}[/tex]Where
(x₁,y₁) are the coordinates of one point of the line
(x,₂,y₂) are the coordinates of a second point of the line
Using the ordered pairs:
(3,-2) as (x₁,y₁)
(-3,16) as (x,₂,y₂)
Calculate the slope as follows:
[tex]\begin{gathered} m=\frac{(-2)-16}{3-(-3)} \\ m=\frac{-18}{3+3} \\ m=-\frac{18}{6} \\ m=-3 \end{gathered}[/tex]So the slope of the linear function is m=-3
To determine the equation you can use the point-slope form:
[tex]y-y_1=m(x-x_1)[/tex]Where
m represents the slope
(x₁,y₁) are the coordinates of one point of the line
I will use the point (3,-2) and the slope m=-3 to determine the equation but you can use either ordered pair to do so.
[tex]\begin{gathered} y-(-2)=-3(x-3) \\ y+2=-3(x-3) \end{gathered}[/tex]Now, what's left is to write the equation in slope-intercept form:
-Distribute the multiplication on the parentheses term:
[tex]\begin{gathered} y+2=(-3)\cdot x-(-3)\cdot3 \\ y+2=-3x-(-9) \\ y+2=-3x+9 \end{gathered}[/tex]-Pass "+2" to the right side of the equal sign by applying the opposite operation to both sides of the equal sign "-2"
[tex]\begin{gathered} y+2-2=-3x+9-2 \\ y=-3x+7 \end{gathered}[/tex]The equation of the linear function is:
[tex]h(x)=-3x+7[/tex]To find the value of h(5), you have to replace the equation of the function with x=5 and calculate the corresponding h(x) value
[tex]\begin{gathered} h(x)=-3x+7 \\ h(5)=-3\cdot5+7 \\ h(5)=-15+7 \\ h(5)=-8 \end{gathered}[/tex]So:
[tex]\begin{gathered} h(x)=-3x+7 \\ \text{and} \\ h(5)=-8 \end{gathered}[/tex]
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