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Sagot :
Ok we have the following system of equations:
[tex]\begin{gathered} 5x+2y=18 \\ 5x-y=36 \end{gathered}[/tex]So the first thing to do is take one of the equations above and clear either x or y. I'm going to pick the second equation and clear y:
[tex]\begin{gathered} 5x-y=36 \\ 5x=36+y \\ 5x-36=y \\ y=5x-36 \end{gathered}[/tex]Now we substitute this result in the first equation:
[tex]\begin{gathered} 5x+2y=5x+2\cdot(5x-36)=18 \\ 5x+10x-72=18 \\ 15x=18+72=90 \\ x=\frac{90}{15}=6 \end{gathered}[/tex]Now that we know x we take the result of clearing y from the second equation and find its value:
[tex]\begin{gathered} y=5x-36 \\ y=5\cdot6-36=30-36 \\ y=-6 \end{gathered}[/tex]So in the end x=6 and y=-6.
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