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Sagot :
We are asked to determine the probability of landing on an odd number and then landing on a 6.
To do that we will use the product rule of probabilities:
[tex]P(AandB)=P(A)P(B)[/tex]Where:
[tex]\begin{gathered} A=\text{ landing on an odd number} \\ B=\text{ landing on a 6} \end{gathered}[/tex]To determine the value of the probability of A we need to have into account that there is only 1 odd number (7) out of 3 possible numbers, therefore, the probability is:
[tex]P(A)=\frac{1}{3}[/tex]Now, to determine the value of the probability of "B" we need to have into account that there is only one number 6 out of 3 numbers therefore, we have:
[tex]P(B)=\frac{1}{3}[/tex]Now, we substitute the values:
[tex]P(AandB)=(\frac{1}{3})(\frac{1}{3})[/tex]Now, we solve the operations:
[tex]P(AandB)=\frac{1}{9}[/tex]Therefore, the probability is 1/9
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