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Sagot :
We are given the following equation
[tex]y=3x-1[/tex]Part A: What is the slope?
The standard equation of a line in slope-intercept form is given by
[tex]y=mx+b[/tex]Where m is the slope and b is the y-intercept.
Comparing the given equation with the standard form, we see that the slope is 3.
m = 3
Option (A) is correct.
Part B: What is the y-intercept?
Comparing the given equation with the standard form, we see that the y-intercept is -1.
b = -1
The y-intercept is the value when the line cuts the y-axis, so the corresponding x-value is 0.
So the point is
(0, -1)
Option (A) is correct
Part C: graph y = 3x - 1
The above equation can be graphed by taking some coordinates (substitute x-values into the function and get the y-values from the function.
When x = -1
y = 3x - 1 = 3(-1) - 1 = -3 - 1 = -4
(-1, -4)
When x = 1
y = 3x - 1 = 3(1) - 1 = 3 - 1 = 2
(1, 2)
When x = 2
y = 3x - 1 = 3(2) - 1 = 6 - 1 = 5
(2, 5)
Let us sketch these points to form a line.
The above is a rough graph for the given equation y = 3x - 1
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