At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Connect with professionals ready to provide precise answers to your questions on our comprehensive Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
Given data:
Weight of the student;
[tex]\begin{gathered} F=mg \\ =556\text{ N} \end{gathered}[/tex]Height;
[tex]h=4.0\text{ m}[/tex]Time;
[tex]t=25\text{ s}[/tex]Part (a)
The work done by the student is given as;
[tex]W=Fh[/tex]Substituting all known values,
[tex]\begin{gathered} W=(556\text{ N})\times(4.0\text{ m}) \\ =2224\text{ J} \end{gathered}[/tex]Therefore, the work done by the student is 2224 J.
Part (b)
The power is defined as the rate of doing work. Mathematically,
[tex]P=\frac{W}{t}[/tex]Substituting alll known values,
[tex]\begin{gathered} P=\frac{2224\text{ J}}{25\text{ s}} \\ =88.96\text{ W} \end{gathered}[/tex]Therefore, the power output of the student is 88.96 W.
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.
