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Sagot :
Let the first number be x and the second number be y.
Since the sum of the numbers is 70, it follows that the equation that shows the sum of the numbers is:
[tex]x+y=70[/tex]The difference between the two numbers is 30, hence, the equation that shows the difference is:
[tex]x-y=30[/tex]The system of equations is:
[tex]\begin{cases}x+y={70} \\ x-y={30}\end{cases}[/tex]Make x the subject of the first equation:
[tex]x=70-y[/tex]Substitute this into the second equation:
[tex]\begin{gathered} 70-y-y=30 \\ \Rightarrow70-2y=30 \\ \Rightarrow-2y=30-70 \\ \Rightarrow-2y=-40 \\ \Rightarrow\frac{-2y}{-2}=\frac{-40}{-2} \\ \Rightarrow y=20 \end{gathered}[/tex]The second number is 20.
Substitute y=20 into the equation x=70-y to find x:
[tex]x=70-20=50[/tex]Answers:
The equation that shows the sum of the numbers is x+y=70.
The equation that shows the difference between the numbers is x-y=30.
The numbers are x=50 and y=20.
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