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ANSWER
[tex]P(S|B)=0.61[/tex]EXPLANATION
We are given that 54% of the members at the club play bridge and swim, and 89% of the members play bridge.
[tex]\begin{gathered} P(\text{BnS)}=0.54 \\ P(B)=0.89 \end{gathered}[/tex]To find the probability that the member swims given that he/she plays bridge, we have to apply conditional probability.
The probability that the member swims given that he/she plays bridge is gotten by dividing the probability that the member plays bridge and swims by the probability that the member plays bridge:
[tex]\begin{gathered} P(S|B)=\frac{P(B\cap S)}{P(B)} \\ \Rightarrow P(S|B)=\frac{0.54}{0.89} \\ P(S|B)=0.61 \end{gathered}[/tex]That is the answer.
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