Answered

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A hair dryer draws 6.0 A when plugged into a 120-V line. (a) What is its resistance? (b) How much charge passes through it in 15 min?

Sagot :

We will have the following:

a)

[tex]R=\frac{120V}{6A}\Rightarrow R=20\Omega[/tex]

b)

[tex]Q=(6A)(15min\ast\frac{60s}{1min})\Rightarrow Q=5400W[/tex]

So, the charge is 5400 W in 15 minutes.

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