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Sagot :
Given:
The number of green balls is G = 6.
The numer of yellow balls is Y = 4.
Explanation:
Determine the total number of balls.
[tex]\begin{gathered} T=6+4 \\ =10 \end{gathered}[/tex]Determine the probability for both selected balls to be green.
[tex]\begin{gathered} P(G)=\frac{6}{10}\cdot\frac{5}{9} \\ =\frac{15}{45} \end{gathered}[/tex]Determine the probability for selected balls to be yellow.
[tex]\begin{gathered} P(Y)=\frac{4}{10}\cdot\frac{3}{9} \\ =\frac{6}{45} \end{gathered}[/tex]Determine the probability for both selected balls to be of same colour.
[tex]\begin{gathered} P=P(G)+P(Y) \\ =\frac{15}{45}+\frac{6}{45} \\ =\frac{21}{45} \\ =\frac{7}{15} \end{gathered}[/tex]
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