At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Explore a wealth of knowledge from professionals across various disciplines on our comprehensive Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
Given:
The number of green balls is G = 6.
The numer of yellow balls is Y = 4.
Explanation:
Determine the total number of balls.
[tex]\begin{gathered} T=6+4 \\ =10 \end{gathered}[/tex]Determine the probability for both selected balls to be green.
[tex]\begin{gathered} P(G)=\frac{6}{10}\cdot\frac{5}{9} \\ =\frac{15}{45} \end{gathered}[/tex]Determine the probability for selected balls to be yellow.
[tex]\begin{gathered} P(Y)=\frac{4}{10}\cdot\frac{3}{9} \\ =\frac{6}{45} \end{gathered}[/tex]Determine the probability for both selected balls to be of same colour.
[tex]\begin{gathered} P=P(G)+P(Y) \\ =\frac{15}{45}+\frac{6}{45} \\ =\frac{21}{45} \\ =\frac{7}{15} \end{gathered}[/tex]
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.
