[tex]\begin{gathered} y-\text{intercept}(0,-13) \\ x-\text{intercept}(\frac{13}{5},0) \end{gathered}[/tex]
Explanation
[tex]y=5x-13[/tex]
the y-intercept is the point where the line intersects the y-axis, it is when x=0
and
the x-intercept is the point where the line intersects the x-axis,this is when y=0
so
Step 1
y-intercept
let x=0 and replace
[tex]\begin{gathered} y=5x-13 \\ y=5\cdot0-13 \\ y=0-13 \\ y=-13 \end{gathered}[/tex]
so, the ordered pair is ( 0,-13)
Step 2
x-intercept
let y=0 and solve for x
[tex]\begin{gathered} y=5x-13 \\ 0=5x-13 \\ \text{add 13 in both sides} \\ 0+13=5x-13+13 \\ 13=5x \\ \text{divide both sides by 5} \\ \frac{13}{5}=\frac{5x}{5} \\ \frac{13}{5}=x \end{gathered}[/tex]
hence, the ordered pair is (13/5, 0)
I hope this helps you
