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What is the location of the vertex on the parabola defined by f(x) = 2x2 + 14x + 11 and in what direction does the parabola open?

What Is The Location Of The Vertex On The Parabola Defined By Fx 2x2 14x 11 And In What Direction Does The Parabola Open class=

Sagot :

Vertex of a parabola

The point where the parabola intersects its axis of symmetry is called the "vertex" and is the point where the parabola is most sharply curved.

The given function is,

[tex]f(x)=2x^2+14x+11[/tex]

We will apply graphical method to obtain the solution to the vertex of the parabola

From the graph above, the vertex of the parabola is (- 3.5, - 13.5) which can also be represented into fraction as

[tex](-\frac{7}{2},-\frac{27}{2})[/tex]

And finally, the parabola opens upward.

Hence, the correct option is Option 2.

View image LinO19348