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A ball is shot out of a cannon at ground level. it's height H in feet after t seconds is given by the function H(t) = 96t - 16t^2. Find H(1), H(5), H(2), and H(4). Why are some of the outputs equal? H(1) = ______ feetH(2)= ______ feetH(4)= ______ feet H(5)= ______ feet

Sagot :

Follow the function we have that

[tex]\begin{gathered} H(1)=96(1)-16(1)^2 \\ =96-16=80 \end{gathered}[/tex]

So H(1) = 80 feet. Now

[tex]\begin{gathered} H(2)=96(2)-16(2)^2 \\ =192-64=128 \end{gathered}[/tex]

So H(2) = 128 feet. Now

[tex]\begin{gathered} H(4)=96(4)-16(4)^2 \\ =384-256=128 \end{gathered}[/tex]

So H(4) = 128 feet. Now

[tex]\begin{gathered} H(5)=96(5)-16(5)^2 \\ =480-400=80 \end{gathered}[/tex]

So H(5) = 80 feet.

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