Answered

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A student pushes a heavy box that is originally stationary across the floor with a force 112 N. What is the coefficient of static friction between the classroom floor and the 140 N box?

Sagot :

Given data:

* The force applied on the heavy box is,

[tex]F_a=112\text{ N}[/tex]

* The weight of the heavy box is,

[tex]w=140\text{ N}[/tex]

Solution:

The frictional force acting on the box is,

[tex]\begin{gathered} F_r=\mu\times w \\ \mu\text{ is the coefficient of friction,} \end{gathered}[/tex]

The frictional force acting on the heavy box is equal to the applied force as the heavy box is not moving under the action of applied force.

Thus,

[tex]\begin{gathered} F_r=F_a \\ \mu\times w=112 \\ \mu\times140=112 \\ \mu=\frac{112}{140} \end{gathered}[/tex]

By simplifying,

[tex]\mu=0.8\text{ }[/tex]

Thus, the coefficient of friction between the floor and the box is 0.8.

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