Given
Graph
Procedure
Let's calculate the area of the figure as the sum of the area of the rectangle plus the area of the triangle.
Let's first calculate the area of the rectangle.
[tex]\begin{gathered} A_r=lw \\ A_r=10\cdot4 \\ A_r=40 \end{gathered}[/tex]Now let's calculate the area of the triangle.
[tex]\begin{gathered} A_t=\frac{1}{2}\cdot b\cdot h \\ A_t=\frac{1}{2}\cdot7\cdot6 \\ A_t=21 \end{gathered}[/tex]The total area would be
[tex]\begin{gathered} A_T=A_t+A_r \\ A_T=40+21 \\ A_T=61 \end{gathered}[/tex]The area of the arrow would be 61 sq in