Answered

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For the function f(x) = x2 + 2x - 15 solve the following.f(x) = 0

For The Function Fx X2 2x 15 Solve The Followingfx 0 class=

Sagot :

Given:

[tex]f\mleft(x\mright)=x^2+2x-15[/tex]

To find: The value of x when

[tex]f(x)=0[/tex]

Explanation:

Since,

[tex]f(x)=0[/tex]

We can write it as,

[tex]\begin{gathered} x^2+2x-15=0 \\ x^2+5x-3x-15=0 \\ x(x^{}+5)-3(x-5)=0 \\ (x+5)(x-3)=0 \\ x=-5,3 \end{gathered}[/tex]

Hence, the solution is x = -5, and 3.

Final answer: The solution is,

[tex]\mleft\lbrace-5,3\mright\rbrace[/tex]

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