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For the following line, name the slope and y-intercept. Then write the equation of the line in slope-interceptform.Slope= y - intercept = (0,_ ) Equation: y =

For The Following Line Name The Slope And Yintercept Then Write The Equation Of The Line In SlopeinterceptformSlope Y Intercept 0 Equation Y class=

Sagot :

Given:

A line that passes the through the points (4, 0) and (0,-3).

Required:

Slope, y-intercept, and the equation of the given line.

Explanation:

As the line passes through the points (4, 0) and (0,-3), the slope is calculated as,

[tex]\begin{gathered} Slope\text{ = }\frac{y_2-y_1}{x_2-\text{ x}_1} \\ Slope\text{ = }\frac{-3\text{ - 0}}{0\text{ - 4}} \\ Slope\text{ = }\frac{-3\text{ }}{-4} \\ Slope\text{ = }\frac{3}{4} \end{gathered}[/tex]

The y-intercept of the given line is the point through which the given line passes on the y-axis which is -3. Therefore the intercept of the given line is -3.

The equation of line in slope point form is given as,

[tex]y\text{ = mx + c}[/tex]

Where m is the slope and c is the y-intercept. Therefore the equation of the line is given as,

[tex]y\text{ = }\frac{3}{4}x\text{ - 3}[/tex]

Answer:

Thus the required equation of line is

[tex]y\text{ }=\text{ }\frac{3}{4}\text{x{\text{ - 3}}}[/tex]

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