Answered

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The sum of three numbers is 154. The first number is 10 more than the second. The third number is 4 times the second. What are the numbers?First number:х5?Second number:000Third number

Sagot :

Let's call those numbers a, b and c.

Since their sum is 154, we have:

a + b + c = 154

Also, since the first number is 10 more than the second, we have:

a = b + 10

And, since the third number is 4 times the second number, we have:

c = 4b

Now, we can use the expressions of a and c in terms of b in the first equation:

a + b + c = 154

b + 10 + b + 4b = 154

6b + 10 = 154

6b = 154 - 10

6b = 144

b = 144/6

b = 24

Then, we can use the value of b to find a and c:

a = b + 10

a = 24 + 10

a = 34

c = 4b

c = 4 * 24

c = 96

Therefore,

• First number: ,34

,

• Second number: ,24

,

• Third number: ,96

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