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Calculate the sum of interior angles of a 6 sided polygon

Sagot :

The sum of interior angles of a polygon can be calculated using the formula below.

[tex]\begin{gathered} S\text{ = }(n-2)\times180^0 \\ \text{Where; } \\ S\text{ = sum of interior angles of the polygon } \\ n\text{ = number of sides of the polygon} \end{gathered}[/tex]

For the given question the polygon is 6 sided, so;

[tex]n\text{ = 6}[/tex]

Substituting the value of n into the formula, we have;

[tex]\begin{gathered} S\text{ = (6-2)}\times180^0 \\ S\text{ = 4}\times180^0 \\ S=720^0 \end{gathered}[/tex]

Therefore, the sum of interior angles of a 6 sided polygon​ is 720 degree

[tex]S=720^0[/tex]

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