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Sagot :
The slope is define as the rate of y coordinate with respect to the x coordinate.
[tex]\text{Slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]In the line D which is parallel to x axis has the constant y coordinate i.e
y = -3
So, for the numerator of the slop for line D is ( -3) - ( -3) = 0
Thus the slope will be express as :
[tex]\begin{gathered} \text{Slope}=\frac{y_2-y_1}{x_2-x_1} \\ \text{Slope}=\frac{-3-(-3)}{x_2-x_1} \\ \text{Slope}=\frac{0}{x_2-x_1} \\ \text{Slope = }0 \end{gathered}[/tex]Thus the slope of line is 0
Now, for the line A :
The line A is parallel to y axis, that is only y coorsinates are changes x is at contant position.
i.e. x = -5
So, substitute the value in the expression for the slope :
[tex]\begin{gathered} \text{Slope}=\frac{y_2-y_1}{x_2-x_1} \\ \text{Slope}=\frac{y_2-y_1}{-5-(-5)_{}} \\ \text{Slope}=\frac{y_2-y_1}{-5+5_{}} \\ \text{Slope = }\frac{y_2-y_1}{0_{}} \\ If\text{ the denominater becomes zero, then the expression is not define} \\ So,\text{ slope of line A is not define} \end{gathered}[/tex]Slope of line A is not define
In the line B and C, the coordinates of x and y aixs are changes countinously
thus thier slopes will be well define.
Answer : Slope of line A is not define.
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