Answered

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write the equation of the line that is perpendicular to the graph of y=3/4x-3, and whose y-intercept is -8

Sagot :

write the equation of the line that is perpendicular to the graph of y=3/4x-3, and whose y-intercept is -8

step 1

Find the slope of the given line

y=(3/4)x-3

the slope is m=3/4

step 2

Find the slope of the perpendicular line

REmember that

If two lines are perpendicular, then the product of their slopes is equal to -1 (inverse reciprocal)

so

the slope of the perpendicular line is

m=-4/3

step 3

Find the equation of the line

we have

m=-4/3

y-intercept is -8

so

b=-8

y=mx+b

substitute

y=-(4/3)x-8

Part 2

write an equation of the line that is parallel to the graph of y=-4x-9, and whose y-intercept is 3

step 1

Find the slope of the given line

y=-4x-9

the lope is m=-4

step 2

Find the slope of the parallel line

Remember that

If two lines are parallel, then their slopes are the same

so

the slope of the parallel line is m=-4

step 3

Find the equation of the line in slope intercept form

y=mx+b

we ahve

m=-4

b=3

substitute

y=-4x+3

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