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Sagot :
Let the hypotenuse is x
The length of the other leg is 9 m shorter than the length of the hypotenuse
The length of second leg = Hypotenuse - 9
The length of second leg = x - 9
the length of one leg of a right triangle is 15 m.
The first leg = 15m
Pythagoras Theorem : In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides
Apply pythagoras for the value of x :
[tex]\begin{gathered} \text{ Hypotenuse}^2=Base^2+Perpendicular^2 \\ x^2=15^2+(x-9)^2 \\ x^2=225+x^2+81-18x \\ x^2-x^2=225+81-18x \\ 18x=306 \\ x=\frac{306}{18} \\ x=17 \end{gathered}[/tex]as x represent the hypotnuese, SO
Hypotenuse = 17m
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