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A 0.86 m tall object is placed 3.35 m away from a lens. If the image is 4.58 m tall, how far away from the lens was the image produced? O

Sagot :

The magnification is the ratio of the image size to the object size. If the image and object are in the same medium, it is just the image distance divided by the object distance:

[tex]M=\frac{i}{o}[/tex]

On the other hand:

[tex]M=\frac{h^{\prime}}{h}[/tex]

Where h' is the size of the image and h is the size of the object.

Therefore:

[tex]\frac{h^{\prime}}{h}=\frac{i}{o}[/tex]

Substitute h'=4.58m, h=0.86m and o=3.35m to find i, the distance from the lens at which the image is produced:

[tex]\begin{gathered} \Rightarrow i=\frac{h^{\prime}}{h}\cdot o \\ =\frac{4.58m}{0.86m}\cdot3.35m \\ =17.84m \end{gathered}[/tex]

Therefore, the image is produced 17.84m away from the lens.

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