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Equation of a Perpendicular BisectorDec 06,9:30:56 PMWatch help videoFind an equation for the perpendicular bisector of the line segment whose endpointsare (-9, -1) and (3, – 7).Answer:Submit Answerattempt 1 out of 3 / problem 1 out of max 1Privacy Policy Terms of ServiceCopyright © 2020 DeltaMath.com. All Rights Reserved.

Equation Of A Perpendicular BisectorDec 0693056 PMWatch Help VideoFind An Equation For The Perpendicular Bisector Of The Line Segment Whose Endpointsare 9 1 And class=

Sagot :

We are given two points which are

(-9, -1) and (3, -7)

Firstly, find the mid point of the two points

Midpoints = x1 + x2 / 2 , y1 + y2 / 2

From the point given

x1 = -9, y1 = -1, x2 = 3 and y2 = -7

Mid-point

x1 + x2 / 2

-9 + 3 / 2

= -6/2

= -3

y1 + y2 / 2

-1 + (-7) / 2

= -1 - 7 / 2

= - 8/2

= -4

The midpoint of the points (-9, -1) and (3, -7) is (-3, -4)

Mid-point = (-3, -4)

Secondly, find the slope

Slope = Rise / Run

Rise = y2 - y1

Run = x2 - x1

Rise = -7 -(-1)

Rise = -7 + 1

Rise = -6

Run = 3 - (-9)

Run = 3 + 9

Run = 12

Slope = Rise / Run

Slope = -6/12

Slope = -1/2

Since it bisect perpendicularly

Hence, m1 x m2 = -1

Where m1 = -1/2

-1/2 x m2 = -1

-m2/2 = -1

Cross-multiply

-m2 = 2 x -1

-m2 = -2

Divide both sides by -1

-m2 /-1 = -2/-1

m2 = 2

The equation of a straight line is

y - y1 = m(x - x1)

y1 = -1 and x1 = -9

y - (-1) = 2(x - (-9)]

y + 1 = 2(x + 9)

y + 1 = 2*x + 2*9

y + 1 = 2x + 18

Make y the subject of the formula

y = 2x + 18 - 1

y = 2x + 18 - 1

y = 2x + 17

The equation is y = 2x + 17

-9

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