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Sagot :
Answer:
123.33mol/L
Explanations:
The formula for calculating the molarity of a solution is expressed as:
[tex]\begin{gathered} \text{Molarity}=\frac{moles\text{ of solute}}{litres\text{ of solution}} \\ \end{gathered}[/tex]Given the following parameters
• Moles, of sucrose (solute) = 0.148 moles
• Litres ,of solution = 0.0012L
Substitute the given parameters into the formula;
[tex]\begin{gathered} \text{Molarity}=\frac{0.148\text{moles}}{0.0012L} \\ \text{Molarity}=123.33\text{mol/L} \end{gathered}[/tex]Therefore the molarity of this solution is 123.33mol/L.
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