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What is the equation of the circle whose diameter has endpoints (10,1) and (-8,1)

Sagot :

Since the endpoints of the diameter are (10, 1) and (-8, 1)

Then the center of the circle is the midpoint of these 2 points

We will use the rule of the midpoint to find the center

[tex]M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]

[tex]\begin{gathered} M=(\frac{10+-8}{2},\frac{1+1}{2}) \\ \\ M=(\frac{2}{2},\frac{2}{2}) \\ \\ M=(1,1) \end{gathered}[/tex]

The center of the circle is (1, 1)

The length of the diameter is the difference between the x-coordinate

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