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This Was The Answer I Got But I Am Not Sure It It Is Correct class=

Sagot :

To find JL

We will first find the value of x

JK = KL

2(x+6) = 3x + 8

2x + 12 = 3x+ 8

subtract 2x from both-side of the equation

12 = 3x-2x + 8

12 = x+ 8

subtract 8 from both-side of the equation

12 - 8 = x+ 8 - 8

4 = x

x=4

JK = 2(x+ 6)

substitute x = 4 into the above

JK = 2(4+6)

JK=2(10)

JK=20

KL =3x+8

substitute x=4 into the above

KL = 3(4) + 8

KL = 12 + 8

KL=20

JL = JK + KL

= 20 + 20

= 40

JL = 40 units

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