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10c - 6(2c - 1) = -2( c- 3) Your answer

Sagot :

10c - 6(2c - 1) = -2( c- 3)

[tex]10c-6\left(2c-1\right)=-2\left(c-3\right)[/tex]

in this case, we have a equation with an unknown value (c9

Step 1

operate to eliminate ()

[tex]\begin{gathered} 10c-(6\cdot2c)-(6)(-1)=-2c+6 \\ 10c-12c+6=-2c+6 \\ 10c-12c+2c=6-6 \\ 12c-12c=0 \\ 0=0 \end{gathered}[/tex]

it means, that for any value of x, it will work

this equation has infinite solutions

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