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5 F2 (g) + 2 NH3 (g) → N2F4 (g) + 6 HF (g)If you reacted 7.78 moles of F2 how many moles of HF would be produced?

Sagot :

1. Write down the balanced chemical reaction .

5 F2 (g) + 2 NH3 (g) → N2F4 (g) + 6 HF (g)

2. Determine mole proportions , then solve

From the above balanced reaction, we can see that :

5 moles of F2 reacts to form : 6 moles of HF ,

so, 7.78moles F2 will give :x moles of HF

Therefore,x mole HF =( 6 moles HF * 7.78 mole F2)/ 5 mole F2

= 6 * 7.78/5

=9.336

≈9.34moles HF

• This means that , if you reacted 7.78 moles of F2 , ,9.34 moles of HF would be produced,.

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