Answered

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A vector has an x-componentof -309 m and a y-componentof 187 m.Find the magnitude and direction of thevector.

Sagot :

In order to find the magnitude we will follow the next formula

[tex]M=\sqrt[]{C^2_x+C^2_y}[/tex]

Cx= -309

Cy=187

We substitute the values

[tex]M=\sqrt[]{(-309)^2+(187)^2}=361.18m[/tex]

Then for the direction we need o use the next formula

[tex]\theta=\tan ^{-1}(\frac{Cy}{Cx})[/tex]

We substitute the variables

[tex]\theta=\tan ^{-1}(\frac{187}{-309})=-31.181[/tex]

In order to obtain the direction we need to add to the angle 180°

the direction is -31.181+180=148.82°

ANSWER

magnitud =361.18

direction =148.82°

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