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Sagot :
Answer: 3Sn (NO2)4 + Pt3N4 → Sn3N4 + 3Pt(NO2)4
Given the equation:
• Sn (NO2)4 + Pt3N4 → Sn3N4 + Pt(NO2)4
(1) The first thing we noticed is that this is a double replacement equation
• ,Sn combines with N4 to form Sn3N4, (,take note that Sn→ Sn3,)
• Pt3 combines with (NO2) to form Pt(NO2)4 ( ,take note that Pt3 → Pt)
(2) Balancing the equation
• Sn (NO2)4 + Pt3N4 → Sn3N4 + Pt(NO2)4 ....(,place 3 infront of Sn in the reactant side .)
• 3,Sn (NO2)4 + Pt3N4 → Sn3N4 + Pt(NO2)4...( ,then place 3 infront of Pt in the product side,)
,• 3,Sn (NO2)4 + Pt3N4 → Sn3N4 + ,3,Pt(NO2)4
Check :
3Sn reactant : Sn3 Product
(NO2)4 reactant : (NO2)4 product
Pt3 reactant : 3Pt product
N4 reactant : N4 product
RHS = LHS ,this means that our equation has now balance.
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