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Sagot :
[tex]\begin{gathered} \text{Given} \\ f(x)=-2(x+8)^2-4 \end{gathered}[/tex]
Since the given is a polynomial with a degree of 2, there are no restrictions to its domain. The domain therefore is
[tex]\text{Domain: }(-\infty,\infty)[/tex]The given function is in the vertex form
[tex]\begin{gathered} f(x)=a(x-h)^2+k \\ \text{where} \\ (h,k)\text{ is the vertex} \end{gathered}[/tex]By inspection, we determine that the vertex of the function is at (-8,-4), and since a = -2, then the parabola opens up downwards. This implied that its output peaks at y = -4, and the graph continues towards negative infinity.
We can conclude therefore that the range is
[tex]\text{Range: }(-\infty,-4\rbrack[/tex]
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