Answered

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Find the quotient. Express the final result using positive integer exponents only (72x^-1 y^4)^-1 / (8x^8y^3)

Sagot :

ANSWER:

[tex]\frac{1}{576x^7y^7}[/tex]

STEP-BY-STEP EXPLANATION:

We have the following function:

[tex]\frac{\left(72x^{-1}y^4\right)^{-1}}{8x^8y^3}[/tex]

We operate to simplify and we are left with the following:

[tex]\frac{72^{-1}x^{-1\cdot-1}y^{4\cdot-1}}{8x^8y^3}=\frac{\frac{1}{72}xy^{-4}}{8x^8y^3}=\frac{1}{72\cdot8\cdot x^8\cdot x^{-1}\cdot y^3\cdot y^4}=\frac{1}{576x^7y^7}[/tex]

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