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Sagot :
Explanation
a uniformly accelerated motion is the one in which the acceleration of the particle throughout the motion is uniform,to fidn the time take we can use the formula:
[tex]\begin{gathered} t=\frac{v_f-v_1}{a} \\ where \\ v_f\text{ is the final velocity} \\ v_{i\text{ }}\text{ is the initail velocity} \\ a\text{ is the acceleration, so} \end{gathered}[/tex]Step 1
a)Let
[tex]\begin{gathered} v_i=6\text{ }\frac{m}{s} \\ v_f=0(\text{ rest\rparen} \\ a=-3\frac{m}{s^2} \end{gathered}[/tex]b) now, replace
[tex]\begin{gathered} t=\frac{v_{f}-v_{1}}{a} \\ t=\frac{0-(-6\frac{m}{s})}{3\frac{m}{s}} \\ t=2\text{ seconds} \end{gathered}[/tex]therefore, the answer is 2 seconds
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