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Sagot :
The first thing we do is to verify that the equation is balanced. We are going to count the atoms of each element on each side of the reaction.
Reagents side:
Carbon (C) = 5 atoms.
Hydrogen (H) = 12 atoms.
Oxygen (O) = 16 atoms.
Products side:
Carbon (C) = 5 atoms.
Hydrogen (H) = 12 atoms.
Oxygen (O) =16 atoms.
We have the same number of atoms on both sides of the reaction. So, the reaction is balanced. Now, we must determine which is the limiting reagent.
For each mole of C5H12 that reacts, 8 moles of oxygen are needed and 5 moles of CO2 and 6 moles of H2O are produced.
So, if we have 2.5 moles of C5H12 we will need:
Moles of O2 = 2.5 moles of C5H12 x 8 = 20 moles of oxygen.
We only have 12 moles of oxygen, we don't have enough moles to react to 2.5 moles of C5H12. So oxygen is the limiting reagent. So we will calculate based on the number of moles of oxygen.
So, for every 8 moles of oxygen 1 mole of C5H12 reacts, if we have 12 moles of the oxygen we divide this amount by 8 to know how many moles of C5H12 react.
Moles of C5H12 that reacts = 12 moles of oxygen / 8 = 1.5 moles of C5H12
For each mole of C5H12 6 moles of H2O are produced. So the number of moles produced will be:
Moles of H2O produced= 1.5 moles of C5H12 x 6 = 9 moles of H2O
So, the maximum amount of H2O that can be produced is 9 moles.
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