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Sagot :
Let's employ the triangle inequality here.
If the sides were to form a triangle.
Then if 3x was the longest side, it must be less than the sum of 15 and 9, being the other 2 sides.
So;
[tex]\begin{gathered} 3x<15+9 \\ 3x<24 \\ x<8 \end{gathered}[/tex]If 3x was the shortest side, then 15 would be the longest side, and thus
3x plus 9 must be greater than 15,
So;
[tex]\begin{gathered} 3x+9>15 \\ 3x>15-9 \\ 3x>6 \\ x>2 \end{gathered}[/tex]So, the range of values for which x must lie is;
[tex]2i.e any values greater than 2 but less than 8.
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