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Sagot :
Solution:
Let x represent Ronald's age, and y represent Megan's age.
Thus,
[tex]\begin{gathered} x\Rightarrow Ronald^{\prime}s\text{ age} \\ y\Rightarrow Megan^{\prime}s\text{ age} \end{gathered}[/tex]Given that Ronald was 1.5 times older than Megan, we have the equation to be represented
[tex]x=1.5y\text{ ---- equation 1}[/tex]If Ronald was 27 years old, we have
[tex]x=27[/tex]Substituting the value of 27 for x into equation 1, we have
[tex]\begin{gathered} 27=1.5y \\ solve\text{ for y by dividing both sides by the coefficient of y,} \\ \frac{27}{1.5}=\frac{1.5y}{1.5} \\ \Rightarrow y=18 \end{gathered}[/tex]This implies that Megan's age is
[tex]18\text{ years}[/tex]
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