Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Discover a wealth of knowledge from professionals across various disciplines on our user-friendly Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
Let's check if the given equation is a special product.
[tex]16x^2+56x+49[/tex]Let,
a = 1st term coefficien
b = 2nd term coefficient
c = constant
We get,
a = 16
b = 56
c = 49
Let's check, you can use this method to check if it is a perfect square binomial:
[tex]\begin{gathered} \text{ 2(}\sqrt[]{a}\text{ x }\sqrt[]{c})\text{ = b ;} \\ (a+c)^2\text{ if b is positive} \\ (a-c)^2\text{ if b is negative} \end{gathered}[/tex][tex]\begin{gathered} 2(\sqrt[]{16}\text{ x }\sqrt[]{49})\text{ = 56} \\ 2(4\text{ x 7) = 56 ; since b is positive, a and c are positive} \\ 2(28)\text{ = 56} \\ 56\text{ = 56} \end{gathered}[/tex]Therefore, the equation is a special product. It is a square of a binomial.
The answer is YES, it is a special product. It is a Square of a Binomial (x + y)².
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.
