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what is the value of 6 × 7 – 3^2 × 9 + 4^3

Sagot :

Starting with the given expression:

[tex]6\cdot7-3^2\cdot9+4^3[/tex]

Follow the hierarchy of operations to find the value.

First, solve potencies and roots. Solve the powers 3^2 and 4^3:

[tex]6\cdot7-3^2\cdot9+4^3=6\cdot7-9\cdot9+64[/tex]

Next, solve the multiplications and divisions:

[tex]6\cdot7-9\cdot9+64=42-81+64[/tex]

Solve the sums and substractions:

[tex]42-81+64=-39+64=25[/tex]

Therefore:

[tex]6\cdot7-3^2\cdot9+4^3=25[/tex]