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Sagot :
Answer:
[tex]atoms\text{ of H}=4.7\times10^{25}atoms[/tex]Explanations:
Given the following parameters
moles of C21H23NO5 = 3.4 moles
Since there are 23 atoms of hydrogen in the compound, hence the moles of hydrogen in the compound is given as:
[tex]\begin{gathered} moles\text{ of H}=23\times3.4 \\ moles\text{ of H}=78.2moles \end{gathered}[/tex]According to the Avogadro's constant
[tex]1mole\text{ of a substance}=6.02\times10^{23}atoms[/tex]Convert the moles of hydrogen to atoms
[tex]\begin{gathered} atoms\text{ of H}=78.2\times6.02\times10^{23} \\ atoms\text{ of H}=470.764\times10^{23} \\ atoms\text{ of H}=4.70764\times10^{25} \\ atoms\text{ of H}=4.7\times10^{25}atoms \end{gathered}[/tex]
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