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Sagot :
The equation is given as
[tex]\frac{3(4x-1)}{2}-3x=\frac{5}{4}-(x+2)[/tex][tex]\begin{gathered} \frac{3(4x-1)-2\ast3x}{2}=\frac{5-4\ast(x+2)}{4} \\ \frac{3(4x-1)-6x}{2}=\frac{5-4x-8}{4} \\ \frac{12x-3-6x}{1}=\frac{-3-4x}{2} \\ (6x-3)=\frac{-3-4x}{2} \\ (6x-3)\ast2=-3-4x \\ 12x-6=-3-4x \\ 12x+4x=-3+6 \\ 16x=3 \\ x=\frac{3}{16} \end{gathered}[/tex]The value of x is 3/16.
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