Answered

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what is the polar form of -3+sqrt3i

Sagot :

Solution

For this case we have the following number given:

[tex]-3+\sqrt[]{3}i[/tex]

We can see that x = -3 and y = - sqrt(3)

The angle is given by:

[tex]\arctan (\frac{-\sqrt[]{3}}{3})=-30=-\frac{\pi}{6}[/tex]

The radius would be:

[tex]r=\sqrt[]{(3)^2+(-\sqrt[]{3})^2}=\sqrt[]{12}[/tex]

And the polar form would be given by:

[tex]z=\sqrt[]{12}(\cos (-\frac{\pi}{6})+i\sin (-\frac{\pi}{6}))\text{ }[/tex]

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