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find the area of the semicircle round to the nearest tenth use 3.14 for pi do not include units with your answer to 22.5 in

Sagot :

Semicrcle area = π•Diameter^2 / 8

. = 3.14 • (2 R)^2/8

. = 3.14• (45)^2/8

. = 3.14• 2025/8= 794.81

Then answer is

Area of semicircle = 795 square inches